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	<title>Comments on: An Interesting Math Problem</title>
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		<title>By: liquid parallax</title>
		<link>http://liquidparallax.com/2006/10/20/an-interesting-math-problem/comment-page-1/#comment-12</link>
		<dc:creator>liquid parallax</dc:creator>
		<pubDate>Tue, 24 Oct 2006 06:29:49 +0000</pubDate>
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		<description>I don&#039;t know where you got that from hank. Your calculator rounds up for decimal place limitation, but actually dividing 3 by 2 by hand (long division shown below) will yield a repeating 6 after the decimal point infinitely.

&#160;&#160;&#160;&#160;&#160;0.66
3 / 2.000
&#160;&#160;&#160;&#160;&#160;18 &#124;
&#160;&#160;&#160;&#160;&#160;&#160;&#160;20
&#160;&#160;&#160;&#160;&#160;&#160;&#160;18 &#124;
&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;20

... sorry if that doesn&#039;t look like a division problem. Anyway, you subtract 18 from 20 and will always end up with a 2, then carry the zero and you are back to square one and add 6 after 6 after 6 after 6 after (you get the picture)...</description>
		<content:encoded><![CDATA[<p>I don&#8217;t know where you got that from hank. Your calculator rounds up for decimal place limitation, but actually dividing 3 by 2 by hand (long division shown below) will yield a repeating 6 after the decimal point infinitely.</p>
<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;0.66<br />
3 / 2.000<br />
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;18 |<br />
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;20<br />
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;18 |<br />
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;20</p>
<p>&#8230; sorry if that doesn&#8217;t look like a division problem. Anyway, you subtract 18 from 20 and will always end up with a 2, then carry the zero and you are back to square one and add 6 after 6 after 6 after 6 after (you get the picture)&#8230;</p>
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		<title>By: hank</title>
		<link>http://liquidparallax.com/2006/10/20/an-interesting-math-problem/comment-page-1/#comment-11</link>
		<dc:creator>hank</dc:creator>
		<pubDate>Mon, 23 Oct 2006 12:00:49 +0000</pubDate>
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		<description>2/3 is not 0.666..... it is 0.666.......7 hence 2/3 + 1/3 = 1!</description>
		<content:encoded><![CDATA[<p>2/3 is not 0.666&#8230;.. it is 0.666&#8230;&#8230;.7 hence 2/3 + 1/3 = 1!</p>
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